# Bar Bending Schedule For Two Way Slab (BBS)

## How to find Two way Slab?

Bars that are placed in shorter span is called **main Reinforcement bar **and in longer span it is called a **distribution Reinforcement bar**.

## How do you prepare bar bending schedule for two-way slab

Examble of Prepare a bar bending schedule (BBS) of two way slab. The slab size is 3 by 4 reinforcement is 16mm@150mm and 10mm@200mm c/c shorter and longer span direction respectively. Assume the clear cover is 20mm?

This Solution is Quantity of Steel in Two way Slab.

## Bar Bending Schedule For Two Way Slab

### Main Reinforcement bars:

First, we find out the total no of bars in the shorter span

#### No of bars

= Total span /spacing

= 3960mm/150mm

= 26.4 say 27 nos of bars

#### Cutting Length:

As bar is placed in shorter span which is 3m.

= Total length of span - 2 x clear cover

= 3000 - 2 x 20

= 2960 mm or 2.960 m

So we have total 27 nos of main bars

#### Total length:

= 27 x 2.960m = 79.92m

## Bar Bending Schedule For one Way Slab

### Quantity of steel Main Reinforcement bar

= d²/162 x length

= 16 x 16/162 x 79.92

= 126.2kg

### Distribution Reinforcement bar:

#### No of bars

= total span/spacing

= 2960 mm/200 mm

= 15.8 say 16 nos

As bar is placed in longer span which is 4m

Cutting Length: = total length — 2 x clear cover

= 4000 - 2 x 20

= 3960 mm or 3.960m

So we have total 16 nos of distribution Reinforcement bar so the total length is

#### Total length

= 3.960 x 16

= 63.36m long bar

## Bar Bending Schedule for Footing [BBS]

### Quantity of steel distribution Reinforcement bar

= d2/162 x length

= 10 x 10/162 x 63.36 = 39.1 kg

Total weight of bars:

= weight of main bar + distribution bar

= 126.2 + 39.1

= 165.3kg.

## Format of Bar Bending Schedule as per Code IS:2502-196

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